Question

Упростите выражение:
(sin2a+sin4a+sin6a+sin8a)/(cos2a+cos4a+cos6a+cos8a)

Answer 1

$\dfrac{\sin2\alpha+\sin4\alpha+\sin6\alpha+\sin8\alpha}{\cos2\alpha+\cos4\alpha+\cos6\alpha+\cos8\alpha}=\dfrac{(\sin2\alpha+\sin8\alpha)+(\sin4\alpha+\sin6\alpha)}{(\cos2\alpha+\cos8\alpha)+(\cos4\alpha+\cos6\alpha)}=\\\\\\=\dfrac{2\sin\dfrac{2\alpha+8\alpha}{2}\cos\dfrac{2\alpha-8\alpha}{2}+2\sin\dfrac{4\alpha +6\alpha }{2}\cos\dfrac{4\alpha -6\alpha }{2}}{2\cos\dfrac{2\alpha +8\alpha }{2}\cos\dfrac{2\alpha -8\alpha }{2}+2\cos\dfrac{4\alpha +6\alpha }{2}\cos\dfrac{4\alpha -6\alpha }{2}}=$

$=\dfrac{2\sin5\alpha\cos3\alpha+2\sin5\alpha\cos\alpha}{2\cos5\alpha\cos3\alpha+2\cos5\alpha\cos\alpha}=\dfrac{2\sin5\alpha(\cos3\alpha+\cos\alpha)}{2\cos5\alpha(\cos3\alpha+\cos\alpha)}=\\\\\\=\dfrac{\sin5\alpha}{\cos5\alpha}=tg\,5\alpha$