Question

Решите систему уравнений: 2x-y=5; x^2+y+2=0

Answer 1

(1;-3), (-3;-11).

Объяснение:

$\left \{ \begin{array}{lcl} {{2x-y=5,} \\ {x^{2} +y+2=0;}} \end{array} \right.\Leftrightarrow \left \{ \begin{array}{lcl} {{y=2x-5,} \\ {x^{2} +2x-5+2=0;}} \end{array} \right.\Leftrightarrow\left \{ \begin{array}{lcl} {{y=2x-5,} \\ {x^{2}+2x-3=0;}} \end{array} \Leftrightarrow\right.$

$\left \{ \begin{array}{lcl} {{y=2x-5,} \\ {\left [ \begin{array}{lcl} {{x=1,} \\ {x=-3;}} \end{array} \right.}} \end{array} \right.\Leftrightarrow \left \left [\begin{array}{lcl} {{\left \{ \begin{array}{lcl} {{x=1,} \\ {y=-3;}} \end{array} \right.} \\ {\left \{ \begin{array}{lcl} {{x=-3,} \\ {y=-11.}} \end{array} \right.}} \end{array} \right.$