Question

Sin l, если cos l/2 - sin l/2 = 3/4

Answer 1

$(cos\frac{ \alpha }{2}-sin\frac{ \alpha }{2})^2=cos^2\frac{ \alpha }{2}+sin^2\frac{ \alpha } {2}-2sin\frac{ \alpha }{2}\cdot cos\frac{ \alpha }{2}=1-sin \alpha =(\frac{3}{4})^2\\\\sin \alpha =1-\frac{9}{16}=\frac{7}{16}$