Question

3x в квадрате - 15 = 0 (x - 3) в квадрате = 100 ( х - 4) в квадрате = 6

Answer 1

$3x^2-15=0, \\ x^2-5=0, \\ (x+\sqrt{5})(x-\sqrt{5})=0, \\ x+\sqrt{5}=0, x_1=-\sqrt{5}, \\ x-\sqrt{5}=0, x_1=\sqrt{5}; \\$

$(x-3)^2=100, \\ (x-3)^2-10^2=0, \\ (x-3+10)(x-3-10)=0, \\ (x+7)(x-13)=0, \\ x+7=0, x_1=-7, \\ x-13=0, x_2=13;$

$(x-4)^2=6, \\ (x-4)^2-(\sqrt{6})^2=0, \\ (x-4+\sqrt{6})(x-4-\sqrt{6})=0, \\ x-4+\sqrt{6}=0, x_1=4-\sqrt{6}, \\ x-4-\sqrt{6}=0, x_2=4+\sqrt{6}.$