Question

Решите систему уравнений: 1) 5x + y = 30 3x - 4y = 41 2) 3u - 4v = 2 9u - 5v = 7 3) 5y + 8z = 81 10y - 3z = -15

Answer 1

1.
$\left \{ {{5x+y=30} \atop {3x-4y=41}} \right. \\ \\ \left \{ {{20x+4y=120} \atop {3x-4y=41}} \right.+ \\ \\ 20x+3x=120+41 \\ 23x=161 \\ x=7 \\ \\ 5x+7=30 \\ 5*7+y=30 \\ 35+y=30 \\ y=-5 \\ \\ otvet:(7;-5) \\ \\ 2.$
2.
$\left \{ {{3u-4v=2} \atop {9u-5v=7}} \right. \\ \left \{ {{9u-12v=6} \atop {9u-5v=7}} \right. - \\ -12v+5v=6-7 \\ -7v=-1 \\ v= \frac{1}{7} \\ \\ 3u-4* \frac{1}{7} =2 \\ 3u- \frac{4}{7} =2 \\ 3u=2 \frac{4}{7}= \frac{18}{7} \\ \\ u= \frac{6}{7} \\ \\ otvet :( \frac{6}{7} ; \frac{1}{7} )$
3.
$\left \{ {{5y+8z=81} \atop {10y-3z=-15}} \right. \\ \left \{ {{10y+16z=162} \atop {10y-3z=-15}} \right. - \\ 16z+3z=162+15 \\ 19z=177 \\ z= \frac{177}{19} =9 \frac{6}{19} \\ \\ 10y-3* \frac{177}{19}=-15 \\ \\ 10y- \frac{531}{19} =-15 \\ \\ 10y=-15+ \frac{531}{19} =-15+27 \frac{18}{19} =12 \frac{18}{19} = \frac{246}{19} \\ \\ y= \frac{246}{190} =1 \frac{56}{190} \\ \\ otvet:(1 \frac{56}{190} ;9 \frac{6}{19} )$