Question

Сократите дробь: 1)(x^2-4)\(x^2+x-6) 2)(x^2-49)\(x^2+9x+14)

Answer 1

1)(x^2-4)\(x^2+x-6)=((x-2)(x+2))/((x-2)(x+3))=(x+2)/(x+3)
2)(x^2-49)\(x^2+9x+14)=((x-7)(x+7))/((x+2)(x+7))=(x-7)/(x+2)

Answer 2

$1) \frac{ x^{2} -4}{ x^{2} +x-6}= \frac{(x-2)(x+2)}{(x-2)(x+3) }= \frac{x+2}{x+3} \\ x^{2} +x-6=0\\D=1+24=25\\ \sqrt{D} =5\\ x_{1} = \frac{-1+5}{2} =2\\ x_{2} = \frac{-1-5}{2} =-3\\$

$2) \frac{ x^{2} -49}{ x^{2} +9x+14} = \frac{(x-7)(x+7)}{(x+2)(x+7)}= \frac{x-7}{x+2} \\ \\ x^{2} +9x+14=0\\D=81-56=25\\ \sqrt{D} =5\\ x_{1} = \frac{-9+5}{2} =-2\\ x_{2} = \frac{-9-5}{2} =-7$