Возведение одночлена в степень (2/3 аб^2)^3

Question

Алгебра: Возведение одночлена в степень (2/3 аб^2)^3

380973599293 · Accepted Answer

V
1) x+π/4 =2π*k , k∈ Z .
x= - π/4 x+2π*k , k∈ Z .
2) sin(3π/2 -x) = -1;
- cosx = -1;
cosx =1;
x=2π*k , k ∈ Z .
3) sin(-x) = -1/2 ;
- sinx = -1/2
sinx= 1/2;
x= (-1)^(k)*π/6+π*k , k ∈Z.
4) tq(x/2) =√3 ; [   (tqx)/2 =√3 ];
x/2  = π/3 +π*k , k ∈ Z .
x=2π/3 +2π*k , k ∈ Z.
5) cos(2x-π/3) =(√3)/2;
[2x - π/3 = - π/6 +2π*k ,k ∈ Z ; 2x - π/3 = π/6 +2π*k ,k ∈ Z.
[2x = π/3  - π/6 +2π*k ,k ∈ Z  ; 2x = π/3 + π/6 +2π*k ,k ∈ Z
[2x = π/6 +2π*k ,k ∈ Z  ; 2x = π/2 +2π*k ,k ∈ Z .

x = π/12 +π*k ,k ∈ Z  ;
x = π/4 +π*k ,k ∈ Z .

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