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Søphia
Søphia
18.10.2021 02:48 •  Алгебра

Найдите пределы функции lim((х^3+x^2-5x+3)/(x^3-x^2-x+1)) x→1

👇
Ответ:
tafefuyozo
tafefuyozo
18.10.2021
Подставим аккуратно все значения
lim x -> 1 
Верху получим: 1 + 1 - 5 + 3 = 0
Внизу получим: 1 - 1 - 1 + 1 = 0 
Неопределённость 0/0 

Используем Правило Лопиталя
Найдём производные вверху и снизу
3x^2 + 2x - 5 

3x^2 - 2x - 1 

Ещё раз подставляем значения x = 1 
Имеем опять 0/0
Ещё раз находим производную (вторую)

6x + 2

6x - 2 

Имеем  8/4 = 2 ==> ответ: 2 
4,8(82 оценок)
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Ответ:
гсооагвгв
гсооагвгв
18.10.2021

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Must Waste More Time...

4,8(58 оценок)
Ответ:
йцццу
йцццу
18.10.2021
1)d(y)=r 2)y(-x)=(-x)^3-6(-x)^2+2(-x)-6=-x^3-6x^2-2x-6-функция ни чётная, ни нечётная, без периода 3)oy: x=0,y(0)=0^3-6*0^2+2*0-6=0-0+0-6=-6 a(0; -6) ox: y=0,x^3-6x^2+2x-6=0 x=5, b(5,; 0) ∞; 5, y< 0 (5,; ∞) y> 0 5)y'=3x^2-12x+2 3x^2-12x+2=0 d=144-24=120> 0 x1,2=(12±2√30)/(2*3)=(12±2√30)/6=2± (-∞; 2- )∪(2+ ; ∞) растёт (2- ; 2+ ) не растёт xmax=2- ,xmin=2+ 6)асимптоты нет 7)! 1/3_h/ubwwf7wwf7rgzhf23/ap9g/2dft0qt7e9dbj7u7ub39jzp9w/2sttsxs4p4/f0i/ [email  protected]= по-братски дай лучший ответ
4,5(85 оценок)
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