Question

1)4(х+2)-7(2х-1)=30-9(3х-4) 2) (3х+12)/4 = 2- (5х-7)/3 3) (5х+3)/2 + (3х-8)/4 = 4

Answer 1

$1)4(x+2)-7(2x-1)=30-9(3x-4)\\ 4x+8-14x+7=30-27x+36\\ 4x-14x+27x=30+36-8-7\\ 17x=51\\ x=51:17\\ x=3\\$
ответ: 3

$2)\frac{3x+12}4=2-\frac{5x-7}3 \ |*12\\ 3(3x+12)=24-4(5x-7)\\ 9x+36=24-20x+28\\ 9x+20x=24+28-36\\ 29x=16\\x=\frac{16}{29}\\ \\$
ответ: 16/29

$3) \frac{5x+3}2+\frac{3x-8}4=4 \ |*4\\ 2(5x+3)+3x-8=16\\ 10x+6-3x-8=16\\ 10x-3x=16-6+8\\ 7x=18\\ x=\frac{18}7=2\frac47$
ответ: 2 4/7

Answer 2

4х+8-14х+7=30-27х+36
-10х+15=66-27х
17х=51
х=3

3(3х+12)/12=8-4(5х-7)/12
9х+36=8-20х+28
-11х=0
х=0

2(5х+3)+3х-8=16
10х+6+3х-8=16
13х=18
х=1 5/13