Question

Arccos (-корень3/2) + arcsin(-корень3/2)

Answer 1

$arccos(- \frac{ \sqrt{3} }{2} )+arcsin(- \frac{ \sqrt{3} }{2} )= \\ \\ = \pi -arccos \frac{ \sqrt{3} }{2}-arcsin \frac{ \sqrt{3} }{2} = \\ \\ = \pi - \frac{ \pi }{6}- \frac{ \pi }{3}= \frac{6 \pi - \pi -2 \pi }{6}= \frac{3 \pi }{6}= \frac{ \pi }{2}$