Question

Нужно! 25a^2-b^2/25a^2-10ab+b^2: (5a^2+ab)*(2b-10a) ^-степень, /-дробь

Answer 1

$\frac{25a^2-b^2}{25a^2-10ab+b^{2}} : (5a^2+ab)*(2b-10a)=$
$\frac{(-2)(5a-b)(5a+b)(5a-b)}{a(5a-b)^2(5a+b)} =\frac{(-2)(5a-b)^2(5a+b)}{a(5a-b)^2(5a+b)} = \frac{-2}{a}$