Question

1. (2x^3+3y^2)^3 2. (3a+2b)^3 3. (5x^7+4x^5)^3 4. (6x^9+1,2x^5)^3 заранее !

Answer 1

$1. (2x^3+3y^2)^3 = (2 x^{3})^{3} +3(2 x^{3})^{2} *3y^{2} +3*2x^{3} *(3y^{2} )^{2} +(3y^{2} )^{3}$
$8x^{9} +3*4x^{6} *3y^{2} +3*2 x^{3} *9y^{4} +27y^{6}$
$8 x^{9} +36 x^{6} y^{2} +54 x^{3} y^{4} +27y^{6}$
2.$(3a+2b)^3=(3a)^3+3(3a)^2*2a+3*3a*(2b)^2+(2b)^3$
$27a^3+3*9a^2*2b+3*3a*4b^2+8b^3$
$27a^3+54a^2b+36ab^2+8b^3$
3.$(5x^7+4x^5)^3=(5x^7)^3+3(5x^7)^2*4x^5+3*5x^7*(4x^5)^2+(4x^5)^3$
$125x^{21} +3*25^{14} *4x^5+3*5x^7*16x^{10} +64x^{15}$
$125 x^{21} +300 x^{19} +240 x^{17} +64 x^{15}$
4.$(6x^9+1,2x^5)^3=216 x^{27} +129,6x^{23}+18*1.2^2*x^{19}+1.2^3*x^{15}$
$216 x^{27} +129.6x^{23}+18( \frac{12}{10})^2*x^{19}+( \frac{12}{10})^3*x^{15}$
$216x^{27}+129.6x^{23}+18( \frac{6}{5})^2*x^{19}+( \frac{6}{5} )^3*x^{15$
$216x^{27}+129.6x^{23}+18 \frac{36}{25} x^{19}+ \frac{216}{125} x^{15}$
$216x^{27}+129.6x^{23}+ \frac{648}{25} x^{19}+ \frac{216}{125} x^{15}$

Answer 2

1. (2x^3+3y^2)^3=(2x^3)^3+3(2x^3)^2*3y^2+3*2x^3*(3y^2)^2+(3y^2)^3=8x^9+36x^6*y^2+54x^3*y^4+27y^6=8x^9+90x^9*y^6+27y^6
2. (3a+2b)^3= 27a^3+3(3a)^2*2b+3*3a(2b)^2+(2b)^3=27a^3+54a^2*b+36ab^2+8b^3=27a^3+90a^3*b^3+8b^3

остальное в том же духе