Question

1.вычислите: а) 411 * 4- 9 б) 6-5 : 6-3 в)(2-2)3 2. : а) (х-3)4 *х14 б)1,5а2в-3 * 4а-3в4

Answer 1

1.

а) 4¹¹·4-9 = 4¹¹⁺¹-9 = 4¹²-9 = 16777216 -9 = 16777207

б) 6⁻⁵ : 6⁻³ = 6⁻⁵⁺³ = 6⁻² = 1/36

в) (2⁻²)³ = 2⁻²·2⁻²·2⁻²=2⁻²⁻²⁻²=2⁻⁶ = 1/64

2. а)

$\displaystyle (x-3)^{4} \cdot x^{14}=(x^{4}-4\cdot 3\cdot x^{3}+6\cdot 3^{2} \cdot x^{2}-4\cdot 3^{3}\cdot x+3^{4})\cdot x^{14}=\\\\=x^{4}\cdot x^{14}-12\cdot x^{3}\cdot x^{14}+54\cdot x^{2}\cdot x^{14}-108\cdot x\cdot x^{14}+81\cdot x^{14}=\\\\=x^{18}-12\cdot x^{17}+54\cdot x^{16}-108\cdot x^{15}+81\cdot x^{14}$

б)

1,5·a²·b⁻³·4·a⁻³·b⁴ = 1,5·4·a²⁻³·b⁻³⁺⁴ = 6·a⁻¹·b¹ = 6·b/a