Question

Найдите 1) f(3), f(0), f(-2), если f(x) =21x-7 2) g(8),g(-3),g(0),если g(x)=x²-10x 3)f(-3),f(6),f(0),если f(x)=

Answer 1

№ 1.

$\boxed{f(x) = 21x-7}$

$\displaystyle f(3) = 21 \cdot 3 - 7 = 63 - 7 = \boxed {56} \\\\f(0) = 21 \cdot 0 - 7 = 0 - 7 = \boxed{-7} \\\\f(-2) = 21 \cdot (-2) - 7 = -42 - 7 = \boxed{-49}$

№ 2.

$\boxed{g(x) = x^2 - 10x }$

$g(8) = 8^2 - 10 \cdot 8 = 64 - 80 = \boxed{-16} \\\\g(-3) = (-3)^2 - 10 \cdot (-3) = 9 + 30 = \boxed{39} \\\\g(0) = 0^2 - 10 \cdot 0 = 0-0 = \boxed{0}$

№ 3.

$\boxed {\displaystyle f(x) = \frac{x-6}{x+4}, \;\;\; x\neq -4}$

$\displaystyle f(-3) = \frac{-3-6}{-3+4} = \frac{-9}{1} = \boxed{ -9} \\\\\displaystyle f(6) = \frac{6-6}{6+4} = \frac{0}{10} =\boxed {0} \\\\\displaystyle f(0) = \frac{0-6}{0+4} = - \frac{6}{4} = \boxed {-1.5}$