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Maximoniko
Maximoniko
06.07.2022 21:34 •  Алгебра

Найдите значение ввражения 4х+3y при x=-3/4,y=-1/6

👇
Ответ:
Подставим данные нам значения в выражения:
4*(-3/4)+3*(-1/6)
сократим дроби:
-3-(1/2)=-3-0,5=-3,5
4,7(32 оценок)
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Ответ:
гсооагвгв
гсооагвгв
06.07.2022

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Must Waste More Time...

4,8(58 оценок)
Ответ:
horarharry
horarharry
06.07.2022

2^x=a

(a²-8a+7)/(a²-5a+4)≤(a-9)/(a-4) +1/(a+6)

a²-8a+7=(a-1)(a-7)

a1+a2=8 U a1*a2=7⇒a1=1 U a2=7

a²-5a+4=(a-1)(a-4)

a1+a2=5 U a18a2=4⇒a1=1 U a2=4

(a-1)(a-7)/[(a-1)(a+4)≤(a-9)/(a-4) +1/(a+6)

(a-7)/(a-4)-(a-9)/(a-4) -1/(a+6)≤0, a≠1

[(a-7)(a+6)-(a-9)(a+6)-(a-4)]/[(a-4)(a+6)]≤0

[(a+6)(a-7-a+9)-(a-4)]/[(a-4)(a+6)]≤0

(2a+12-a+4)/[(a-4)(a+6)]≤0

(a+16)/[(a-4)(a+6)]≤0

a=-16  a=4  a=-6

          _            +              _        _        +

[-16](-6)(-1)(4)

a≤-16⇒2^x≤-16 нет решения

-6<a<-1⇒-6<2^x<-1 нет решения

-1<a<4⇒-1<2^x<4⇒x<2

x∈(-∞;2)

4,5(45 оценок)
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