Question

Вычислить, желательно подробно,чтобы понять! a)3^7*81 3^10 б)(5x/4)^2 в)-6^3+(-2)^6

Answer 1

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Answer 2

A)
$\frac{ {3}^{7} \times 81 }{ {3}^{10} } = \frac{ {3}^{7} \times {3}^{4} }{ {3}^{10} } = \frac{ {3}^{7 + 4} }{ {3}^{10} } = \frac{ {3}^{11} }{ {3}^{10} } = {3}^{11 - 10} = {3}^{1} = 3$
б)
$( \frac{5x}{4} ) ^{2} = \frac{(5x) ^{2} }{ {4}^{2} } = \frac{ {5}^{2} \times {x}^{2} }{ 16 } = \frac{25}{16} {x}^{2} = 1 \frac{9}{16} {x}^{2}$
в)
$- {6}^{3} + ( - 2) ^{6} = - (3 \times 2) ^{3} + ( - 2) ^{3} \times ( - {2})^{3} = - {3}^{3} \times {2}^{3} + ( - 8) \times ( - 8) = - 27 \times 8 + 64 = 8 \times ( - 27 + 8) = 8 \times ( - 19) = - 152$