Question

Найдите сумму многочленов 4n^2-n и 2n^2-2n

Answer 1

(4n^2-n) + (2n^2-2n)=6n^2-3n=3n(2n-1)

Answer 2

$\left(4n^2-n\right)+\left(2n^2-2n\right)=4n^2-n+2n^2-2n= \\ =4n^2+2n^2-n-2n =\\ =4n^2+2n^2-3n= \\= 6n^2-3n \\ \\ \mathfrak{OTBET} : 6n^2-3n$