Question

Cosa=корень3/2 какие точки ? +корни на [p; 5p/2]

Answer 1

$Cos \alpha = \frac{ \sqrt{3} }{2} \\\\ \alpha _{1}= \frac{ \pi }{6}+2 \pi n\\\\ \alpha _{2} =- \frac{ \pi }{6}+2 \pi n\\\\\\ \pi \leq \frac{ \pi }{6}+2 \pi n \leq \frac{5 \pi }{2} \\\\ \frac{5 \pi }{6} \leq 2 \pi n \leq \frac{7 \pi }{3}\\\\ \frac{5}{12} \leq n \leq \frac{7}{6} \\\\n=1 , \alpha = \frac{ \pi }{6} +2 \pi = \frac{13 \pi }{6}\\\\\\ \pi \leq - \frac{ \pi }{6} +2 \pi n \leq \frac{5 \pi }{2} \\\\ \frac{7 \pi }{6} \leq 2 \pi n \leq \frac{8 \pi }{3}$

$\frac{7}{12} \leq n \leq \frac{4}{3}\\\\n=1 , \alpha =- \frac{ \pi }{6}+2 \pi = \frac{11 \pi }{6}$

ответ:  $\frac{11 \pi }{6} ; \frac{13 \pi }{6}$

Answer 2

Сosa=√3/2
a=-π/6+2πk U a=π/6+2πk
π≤-π/6+2πk≤5π/2
6≤-1+12k≤15
7≤12k≤16
7/12≤k≤16/12
k=1   x=-π/6+2π=11π/6
π≤π/6+2πk≤5π/2
6≤1+12k≤15
5≤12k≤14
5/12≤k≤14/12
k=1  x=π/6+2π=13π/6