Question

A) 2x^2-3x=0 б) 16x^2=49 в)x^2-2x-35=0

Answer 1

$2 {x}^{2} - 3x = 0 \\ x(2x - 3) = 0 \\ x1 = 0 \\ x2 = \frac{3}{2}$
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$16 {x}^{2} = 49 \\ \\ {x}^{2} = \frac{49}{16} \\ \\ x1 = \frac{7}{4} \\ \\ x2 = - \frac{7}{4}$
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${x}^{2} - 2x - 35 = 0 \\ d = ( - 2) ^{2} - 4 \times ( - 35) = 4 + 140 = 144 \\ \\ x1 = \frac{2 + \sqrt{144} }{2} \\ \\ x2 = \frac{2 - \sqrt{144} }{2} \\ \\ x1 = \frac{14}{2} \\ \\ x2 = - \frac{10}{2} \\ x1 = 7 \: \: \: \: \: x2 = - 5$
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Готово.

Answer 2

Удачи))

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