Question

7a/a^2-4b^2-7/a-2b 10 за решение ответ я знаю​

Answer 1

$\frac{4a}{a^{2}-64b^2}-\frac{4}{a+8b}=\frac{4a}{a^{2}-(8b)^2}-\frac{4}{a+8b}=$

$=\frac{4a}{(a-8b)(a+8b)}-\frac{4}{a+8b}=\frac{4a-4*(a-8b)}{(a-8b)(a+8b)}=$

$=\frac{4a-4a+32b}{(a-8b)(a+8b)}=\frac{32b}{(a-8b)(a+8b)}=\frac{32b}{a^2-64b^2}$