Газ получил 300 дж теплоты при этом он совершил работу в 100дж на сколько изменилась его внутренния этерги

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Ответ:

Маринка200711

10.10.2021

дельтаU=Q-A.

дельтаU=300-100=200.

НА 200 Дж изменилась внутренняя энергия

4,4(66 оценок)

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Ответ:

Marcelyn

10.10.2021

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4,6(70 оценок)

Ответ:

пматмг

10.10.2021

Скорость нагревания уменьшается с ростом разности температуры воды в кастрюле и комнатной температуры, только в самом начале нагревания можно считать, что вся подведенная энергия идет на увеличение температуры воды. Если бы и дальше не было потерь, то вода за эти 14 минут и 20 секунд (то есть за 860 секунд) нагрелась бы на 43 градуса, получив энергию 86 кДж. С учетом потерь в окружающую среду она нагрелась только на 20 градусов, тогда можно найти величину потерь: 86 умножить на 23и разделить на 43 = 46 кДж

4,7(10 оценок)

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