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ayaermek
ayaermek
12.08.2020 21:16 •  Физика

При каком давлении газ, занимавший объем 2,3 10-4 м3, будет сжат до объема 2,25 10-4 м3, если температура газа останется неизменной. первоначальное давление газа равно 0,95 105 па

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Ответ:
floratv32
floratv32
12.08.2020
По уравнению клапейрона\frac{p1V1}{T1} = \frac{p2V2}{T2}

тк T=const то 
p1V1=p2V2
p2=\frac{p1V1}{V2} = \frac{2.3* 10^{-4}*0.95* 10^{5} }{2.25* 10^{-4} } =0.97*10^5
4,6(35 оценок)
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Ответ:
Aynur123455
Aynur123455
12.08.2020

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Must Waste More Time...


Дано: U₁=15V, I₂=50мА, U₃=30V, R1=1000 , R₂=700 , R₃=500 Знайти: P₁₂ , Ii , Ui , Pu₁ ?
4,8(51 оценок)
Ответ:
n1kitat
n1kitat
12.08.2020

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Must Waste More Time...


3. 200 грам ВОДЫ при температуре 15 °С смешали с 300 грамм водой при температуре 90°с. Найдите устан
4,6(84 оценок)
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