Δ АБД прямоугольный тк параллел-д прямоугольный значит по теореме пифагора ВД=√(АВ²+АД²)=5, АА1=ДД1 высоты параллелепипеда Δ БДД1 прямоугольный (тк ребра параллелепипеда перпендикулярны граням, а значит и прямым на этих гранях) и по т. Пифагора ВД1=√(БД²+ДД1²)=√(25+144)=√169=13 P=ВД+ДД1+ВД1=5+12+13=30
I was tired. (–)
Kris spoke English. (–)
His sister was a model. (?)
I liked my phone. (–)
Masha read magazine. (?)
They were students. (?)
This shop opened at 9 o’clock. (?)
She was pretty. (?)
Tom lied. (–)
Marina wore skirts. (–)
I was tired. (–)
Kris spoke English. (–)
His sister was a model. (?)
I liked my phone. (–)
Masha read magazine. (?)
They were students. (?)
This shop opened at 9 o’clock. (?)
She was pretty. (?)
Tom lied. (–)
Marina wore skirts. (–)
I was tired. (–)
Kris spoke English. (–)
His sister was a model. (?)
I liked my phone. (–)
Masha read magazine. (?)
They were students. (?)
This shop opened at 9 o’clock. (?)
She was pretty. (?)
Tom lied. (–)
Marina wore skirts. (–)
Δ БДД1 прямоугольный (тк ребра параллелепипеда перпендикулярны граням, а значит и прямым на этих гранях) и по т. Пифагора ВД1=√(БД²+ДД1²)=√(25+144)=√169=13
P=ВД+ДД1+ВД1=5+12+13=30