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АВ²=7²+4²-2·7·4·cos 30°=49+16-28√3 ⇒ AB < 7
Наибольшая из площадей боковых граней - грань ВСС₁В₁
Значит ВВ₁=СС₁= 28 см²: 7 см = 4 см
Н ( призмы) = ВВ₁ = 4 см
V=S(основания)· H= 1/2· 4·7· sin 30°· 4=112 куб см