Program pr_1;
var
x,y,sum, umn: integer;
begin
write ('x=');
readln (x);
write ('y=');
readln (y);
sum:=x+y;
umn:=x*y;
writeln ('sum=",sum);
writeln ('umn=", umn);
readln;
end.

x-37
y-38

Question

Информатика: Program pr_1; var x,y,sum, umn: integer; begin write ( x= ); readln (x); write ( y= ); readln (y); sum:=x+y; umn:=x*y; writeln ( sum= ,sum); writeln ( umn= , umn); readln; end. x-37 y-38​

HFccv · Accepted Answer

Program Project1;

var m:array of integer; n, i, summ:integer;

begin
repeat
    write('n: '); readln(n);
    SetLength(m, Length(m)+1);
    m[Length(m)-1]:=n;
until n=0;
SetLength(m, Length(m)-1);

n:=0; summ:=0;
for i:=0 to Length(m)-1 do begin
    if m[i]>12 then begin
      inc(n);
      inc(summ, m[i]);
    end;
end;

Writeln('Result:=', summ/n);

readln;
end.

2)

program Project1;

var n, t, res: integer;

begin
write('N:=');readln(n);
res:=1;
while n>0 do begin
    t:=(n mod 10);
    if t<4 then res:=res*t;
    n:=n div 10;
end;

writeln('Result:=', res);

readln;
end.

Program pr_1;varx,y,sum, umn: integer;beginwrite ('x=');readln (x);write ('y=');readln (y);sum:=x+y;umn:=x*y;writeln ('sum=",sum);writeln ('umn=", umn);readln;end.x-37y-38​

MOGZ ответил

Program pr_1;
var
x,y,sum, umn: integer;
begin
write ('x=');
readln (x);
write ('y=');
readln (y);
sum:=x+y;
umn:=x*y;
writeln ('sum=",sum);
writeln ('umn=", umn);
readln;
end.

x-37
y-38