N=int(input())
a=[]
sum = 0
f = 0
c = 0
for i in range(N):
l = int(input())
sum = sum + l
a.append(l)
if N == 1:
print(1)
else:
ans = []
for i in range(N-1, 0, -1):
if a[i] > a[i-1]:
if sum > a[-1] or (sum > a[i+1] and f == 1):
for k in range(c+1):
ans.append(1)
c = 0
f = 1
else:
ans.append(0)
f = 0
elif a[i] == a[i-1]:
c += 1
else:
ans.append(0)
f = 0
sum=sum-a[i]
ans = ans[::-1]
print(0)
for i in range(c):
print(0)
for i in ans:
print(i)
Объяснение:
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#include <iostream>
using namespace std;
int main(){ cout << "Vvedute kol-vo ocenok" << endl;
int n,i,a,Four,Five; n = i = a = Four = Five = 0;
cin >> n;
for (i = 1; i <= n; i++) { cin >> a; if (a == 4){ Four++;} else if (a == 5) { Five++; } } if (Four > Five){ cout << "Four" << endl;} else if (Five > Four) { cout << "Five" << endl; } else { cout << "Equal"<< endl; } cout << "Kol-vo 4: " << Four << " Kol-vo 5: " << Five << endl; return 0;}