ответы: 32 150 35 0 35 1
Задание 1:
a = 4b = 4b = a/2*b = 4/2*4 = 2*4 = 8a = 2*a + 3*b = 2*4 + 3*8 = 8 + 24 = 32Задание 2:
k = 5m = 90k = m-k*2 = 90-5*2 = 90-10 = 80m = k*3-m = 80*3-90 = 240-90 = 150Задание 3:
a = 10b = 1b = a/2*b = 10/2*1 = 5*1 = 5a = 2*a + 3*b = 2*10 + 3*5 = 20 + 15 = 35Задание 4:
a = 0b = 2b = 2 + a + 4*b = 2 + 0 + 4*2 = 2 + 8 = 10a = b/2*a = 10/2*0 = 5*0 = 0Задание 5:
a = 8b = 3a = 3 * a - b = 3 * 8 - 3 = 24 - 3 = 21b = ( a / 3 ) * ( b + 2 ) = ( 21 / 3 ) * ( 3 + 2 ) = 7 * 5 = 35Задание 6:
a = 7b = 2a = b*4 + a*3 = 2*4 + 7*3 = 8 + 21 = 29b = 30 - a = 30 - 29 = 1Пример работы:
typedef size_t uint32;
mt19937 gen{ random_device()() };
uniform_int_distribution<uint32> uid(20, 100);
const uint32 N = 10;
int main()
{
uint32 arr[N], pos{0}, neg{0};
for (uint32 i = 0; i < N; ++i) {
arr[i] = uid(gen);
cout << arr[i] << " ";
if (arr[i] % 2 == 0) ++pos;
else ++neg;
}
cout << endl << pos << "/" << neg << endl;
system("pause");
}
2)
typedef size_t uint32;
mt19937 gen{ random_device()() };
uniform_int_distribution<uint32> uid(0, 100);
const uint32 N = 10;
int main()
{
uint32 arr[N], lf{ 0 }, hf{ 0 }, sum1{ 0 }, sum2{ 0 };
for (uint32 i = 0; i < N; ++i) {
arr[i] = uid(gen);
cout << arr[i] << " ";
if (arr[i] >= 50) {
++lf;
sum1 += arr[i];
} else {
++hf;
sum2 += arr[i];
}
}
cout << endl << sum1 / lf << "/" << sum2 / hf << endl;
system("pause");
}