x
2
+
y
2
=
16
...
...
...
...
...
...
.
.
(
1
)
x + y = 4 (2)
rearrange (2) to y = 4 - x (could do x = 4 - y )
substitute y = 4 - x into (1)
hence:
x
2
+
(
4
−
x
)
2
=
16
⇒
x
2
+
16
−
8
x
+
x
2
=
16
and
2
x
2
−
8
x
+
16
−
16
=
0
⇒
2
x
2
−
8
x
=
0
factor and solve : 2x(x - 4 ) = 0
⇒
x
=
0
,
x
=
4
substitute these values into y = 4 - x , to find corresponding values of y.
x = 0 : y = 4 - 0 = 4 → (0 , 4)
x = 4 : y = 4 - 4 = 0 → (4 , 0 )
These are the points of intersection with the line x +y = 4 and the circle
x
2
+
y
2
=
16
Answer link
Объяснение:
a:array of integer;
i,b,c:integer;
BEGIN
write('Введите размер массива - ');
readln(b);
setlength(a,b);
writeln('Введите элементы массива - ');
for i:=0 to b-1 do begin
readln(a[i]);
if a[i] mod 2 = 0 then c:=c+a[i];
end;
writeln('Сумма четных элементов массива - ',c);
END.