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lian restaurant. He couldn't
(3)
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Adam wasn't interested inTraveller
e verbs in
lian restaurant. He couldn't
(3)
(work
iness, his own restaurant. At
Adam wasn't interested inTraveller
e verbs in
lian restaurant. He couldn't
(3)
(work
iness, his own restaurant. At
Adam wasn't interested inTraveller
e verbs in
lian restaurant. He couldn't
(3)
(work
iness, his own restaurant. At
Adam wasn't interested inTraveller
e verbs in
lian restaurant. He couldn't
(3)
(work
iness, his own restaurant. At
Adam wasn't interested inTraveller
e verbs in
lian restaurant. He couldn't
(3)
(work
iness, his own restaurant. At
Adam wasn't interested inTraveller
e verbs in
lian restaurant. He couldn't
(3)
(work
iness, his own restaurant. At
Adam wasn't interested inTraveller
e verbs in
lian restaurant. He couldn't
(3)
(work
iness, his own restaurant. At
Adam wasn't interested inTraveller
e verbs in
lian restaurant. He couldn't
(3)
(work
iness, his own restaurant. At
Adam wasn't interested inTraveller
e verbs in
lian restaurant. He couldn't
(3)
(work
iness, his own restaurant. At
Adam wasn't interested inTraveller
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lian restaurant. He couldn't
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ответ:
. в нужно вывести все составные числа из промежутка [2; n]. код программы:
program lab3;
var i,n,j,s,l: integer;
m: real;
begin
readln (n);
for i: =2 to n do
begin
s: =trunc (sqrt (i));
for l: =2 to s do
begin
m: = i mod l;
if m=0 then
write (' ',i);
end;
end;
end.
но проблема - как только s становится больше 2, составные числа начинают несколько раз повторятся, т.к., например 12 делится и на 2 и на 3. вопрос: как мне сделать выход из цикла после первого успешного деления?
var
i, n, j, s, l: integer;
m: real;
begin
readln(n);
for i : = 2 to n do
begin
s : = trunc(sqrt(i));
for l : = 2 to s do
begin
m : = i mod l;
if m = 0 then
begin
write(' ', i);
break;
