Объяснение:
Mr(Na2O) = 23*2+16 = 62
W(Na) = Ar(Na) *n / Mr(Na2O) *100% = 23*2 / 62 *100% =74%
W(O) = Ar(O) *n / Mr(Na2O) *100% = 16 *1 / 62 *100% =26%
Mr(SrO) = 88 + 16 =104
W(Sr) = Ar(Sr) * n / Mr(SrO) *100% = 88 *1 / 104 *100% =85%
W(O) = Ar(O) *n / Mr(SrO) *100% = 16*1 / 104 *100% =15%
Mr(Al2O3) = 27*2 + 16*3 = 102
W(Al) = Ar(Al) *n / Mr(Al2O3) *100% = 27*2 / 102 *100% =53%
W(O) = Ar(O) *n / Mr(Al2O3) *100% = 16*3 / 102 *100% =47%
Mr(MnO2) = 55 + 16*2 =87
W(Mn) = Ar(Mn) * n / Mr(MnO2) *100% = 55 *1 / 87 *100% =63%
W(O) = Ar(O) *n / Mr(MnO2) *100% = 16*2 / 87 *100% =37%
Mr(V2O5) = 51*2 + 16*5 = 182
W(V) = Ar(V) *n / Mr(V2O5) *100% = 51*2 / 182 *100% = 56%
W(O) = Ar(O) *n / Mr(V2O5) *100% = 16*5 / 182 *100% =44%
Дано: m (N2) = 14г найти: V (Н2) =?
N2 + 3H2 ---> 2NH3 (NH3 – аммиак)
ν = 1 моль ν = 3 моль
М = 28г/моль Vm = 22.4л/моль
m = 28г V = 67, 2 л
14/28 = х / 67,2 х = 14 * 67,2 / 28 = 33,6л
ответ: V (Н2) = 33,6л
Объяснение:
Mr(Na2O) = 23*2+16 = 62
W(Na) = Ar(Na) *n / Mr(Na2O) *100% = 23*2 / 62 *100% =74%
W(O) = Ar(O) *n / Mr(Na2O) *100% = 16 *1 / 62 *100% =26%
Mr(SrO) = 88 + 16 =104
W(Sr) = Ar(Sr) * n / Mr(SrO) *100% = 88 *1 / 104 *100% =85%
W(O) = Ar(O) *n / Mr(SrO) *100% = 16*1 / 104 *100% =15%
Mr(Al2O3) = 27*2 + 16*3 = 102
W(Al) = Ar(Al) *n / Mr(Al2O3) *100% = 27*2 / 102 *100% =53%
W(O) = Ar(O) *n / Mr(Al2O3) *100% = 16*3 / 102 *100% =47%
Mr(MnO2) = 55 + 16*2 =87
W(Mn) = Ar(Mn) * n / Mr(MnO2) *100% = 55 *1 / 87 *100% =63%
W(O) = Ar(O) *n / Mr(MnO2) *100% = 16*2 / 87 *100% =37%
Mr(V2O5) = 51*2 + 16*5 = 182
W(V) = Ar(V) *n / Mr(V2O5) *100% = 51*2 / 182 *100% = 56%
W(O) = Ar(O) *n / Mr(V2O5) *100% = 16*5 / 182 *100% =44%