Exercise 1 Open the brackets using the correct form of the Passive Voice. (Раскройте скобки, используйте - id1182665820210105 от sab1na666 05.01.2021 00:00

Question

Химия: Exercise 1 Open the brackets using the correct form of the Passive Voice. (Раскройте скобки, используйте Passive Voice). 1 The equipment (to test) by 2 o’clock yesterday. 2 Many hotels (to built) lately. 3 The new assembly shop (to put) into operation by June last year. 4 The Letter of Credit (to open) by the time you return to New Delhi. 5 A new model (to launch) by the end of the month. 6 The terms of payment (not to discuss) yet. 7 After the contract (to sign) we went to the restaurant. 8 When

sab1na666 · Accepted Answer

1/
Дано:
m(H2O) =36 г
m(BaO) -?
M(H2O) = 18 г/моль
n(H2O) = m(H2O)/M(H2O) = 36 г/18 г/моль = 2 моль
BaO + H2O = Ba(OH)2
Из стехиометрических коэффициентов уравнения реакции следует, что n(BaO) = n(H2O) = 2 моль
М(ВаО) = 153 г/моль
m(BaO) = n(BaO)*M(BaO) = 2 моль*153 г/моль = 306 г
ответ: 306 г
4.
M(K2SO3) = 39*2+32+48=78+80=158 г/моль
ω(К) = 78 г/158 г =0,4937 или 49,37%
5.
m(HCl) = 140 г *0,1 = 14 г
14 г х г
HCl + AgNO3 = AgCl↓ + HNO3
36,5 г 143,5 г
х= 55,04 г
ответ: 55,04 г
6.
m(p-pa сахара) = 100 г+500 г = 600 г
ω(сахара) = 100 г/600 г =0,1667 или 16,67%
ответ: 16,67%
7. n(H3PO4) = m(H3PO4)/M(H3PO4) = 9.8 г/98 г/моль = 0,1 моль
ответ: 0,1 моль

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