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14.8 г
Объяснение:
Уравнение реакции:
CH3-COOH + CH3-OH <=> CH3-COO-CH3 + H2O ( метиловый эфир уксусной кислоты)
Находим молярные массы:
М(CH3COOH) = 12+1*3+12+16*2+1 = 60 г/моль
М(CH3OH) = 12+1*3+16+1 = 32г/моль
M(CH3-COO-CH3) = 12+1*3+12+16*2+12+1*3 = 74 г/моль
Смотрим сколько вещества прореагировало по факту:
n(CH3COOH) = 24:60 =0.4 моль
n(CH3OH) = 6.4:32 = 0.2 моль
В избытке - кислота, в недостатке - спирт, значит в результате реакции не может получиться больше чем 0.2 моль эфира.
В 1 моль метилацетата 74 г вещества, значит в 0.2 моль 74*0.2 = 14.8 г.