Объяснение:
Mr(Ba(NO3)2) = 137 + 14*2 + 16*6 = 261
W(O) = Ar(O) *n / Mr(Ba(NO3)2) *100% = 16*6 / 261 *100% =37%
Mr(Ca3(PO4)2 =40*3 + 31*2 + 16*8 =310
W(O) = Ar(O) *n / Mr(Ca3(PO4)2) *100% = 16*8 / 310 *100% =41%
Mr(Al2(SO4)3) = 27*2+32*3 +16*12 =342
W(O) = Ar(O) *n / Mr(Al2(SO4)3) *100% = 16*12 / 342 *100% =56%
Mr(Ca(NO3)2 = 40 + 14*2 + 16*6 =164
W(O) = Ar(O) *n / Mr(Ca(NO3)2 *100% = 16*6 / 164 *100% = 58,5%
Mr(Na2SO4) = 23*2 + 32 + 16*4 = 142
W(Na) = Ar(Na) *n / Mr(Na2SO4) *100% = 23*2 / 142 *100% =32%
W(S) = Ar(S) *n / Mr(Na2SO4) *100% = 32*1 / 142 *100% =22%
W(O) = Ar(O) *n / Mr(Na2SO4) *100% = 16*4 / 142 *100% =46%
Mr(Ba(NO3)2) = 137 + 14*2 + 16*6 = 261
W(Ba) = Ar(Ba) *n / Mr(Ba(NO3)2) *100% = 137 *1 / 261 *100% = 52%
W(N) = Ar(N) *n / Mr(Ba(NO3)2 *100% = 14*2 / 261 *100% =11%
W(O) = Ar(O) *n / Mr(Ba(NO3)2) *100% = 16*6 / 261 *100% = 37%
+ - + 2- + 2-
1)2KOH+H2SO4=K2SO4+2H2O
+ - + 2- + 2-
2K+2OH+2H+SO4=2K+SO4+2H2O
+ -
2H+2OH=2H2O
+ 2- 2+ - + -
2) K2SO4+Ba(Cl)2=2KCl+BaSO4(осадок)
+ 2- 2+ - + -
2K+SO4+Ba+2Cl=2K+2Cl+BaSO4
2+ 2-
Ba+SO4=BaSO4
+ - + - + -
3)KCl+AgNO3=KNO3+AgCl
+ - + - + -
K+Cl+Ag+NO3=K +NO3+AgCl
+ -
Ag+Cl=AgCl
ответ:w(O) = Ar(O)·n(O)\Mr(в-ва)
Mr(Fe₂O₃) = 56·2+16·3 = 160
w(O) = 16·3\160 = 0,3 \ 30%
Mr(Fe₃O₄) = 56·3+16·4 = 232
w(O) = 16·4\232 = 0,276 \ 27,6%
Fe₂O₃ ≥ Fe₃O₄
Mr(CrO) = 52=16 =68
w(O) = 16·1\68 = 0,235 \ 23,5%
Mr(CrO₃) = 52+16·3=100
w(O) = 16·3\100 = 0,48\ 48%
СrO ≤ CrO₃
Mr(SO₂) =32+16·2=64
w(O) = 16·2\64 = 0,5 \ 50%
Mr(SO₃) =32+16·3=80
w(O) = 16·3\80 = 0,6 \ 60%
SO₂ ≤ SO₃