формула W = (n*Ar) / Mr * 100%
в каждом действии я не стала писать умножение на 100%.
H2S:
w(H) = 2 * 1 / 34 = 5,88%
w(S) = 1*32 / 34 = 94,1%
NH4Cl:
w(N) = 1 * 14 / 53,5 = 26,2%
w(H) = 4 * 1 / 53,5 = 7,5%
w(Cl) = 1 * 35,5 / 53,5 = 66,4%
Ca(H2PO4)2:
w(Ca) = 1*40 / 234 = 17%
w(H) = 4*1 / 234 = 1,7%
w(P) = 2 * 31 / 234 = 26,5%
w(O) = 8*16 / 234 = 54,7%
CaCl2:
w(Ca) = 1*40 / 111 = 36%
w(Cl) = 2*35,5 / 111 = 64%
Cu2CO3(OH)2
w(Cu) = 2*64 / 222 = 57,65%
w(C) = 1*12 / 222 = 5,4%
w(o) = 3+2 * 16 / 222 = 36%
w(H) = 2 * 1 / 222 = 0,9%
H2SO4:
w(H)= 2*1 / 98 = 2,04%
w(S) = 1*32 / 98 = 32,65%
w(O) = 4*16 / 98 = 65.3%
H2S:
M(H2S)=34
w(H) = 2•1 / 34 = 5,88%
w(S) = 1•32 / 34 = 94,1%
NH4Cl:
M(NH4Cl)=53,5
w(N) = 1•14 / 53,5 = 26,2%
w(H) = 4•1 / 53,5 = 7,5%
w(Cl) = 1•35,5 / 53,5 = 66,4%
Ca(H2PO4)2:
M(Ca(H2PO4)2)=234
w(Ca) = 1•40 / 234 = 17%
w(H) = 4•1 / 234 = 1,7%
w(P) = 2•31 / 234 = 26,5%
w(O) = 8•16 / 234 = 54,7%
CaCl2:
М(CaCl2)=111
w(Ca) = 1•40 / 111 = 36%
w(Cl) = 2•35,5 / 111 = 64%
Cu2CO3(OH)2:
М(Cu2CO3(OH)2)=222
w(Cu) = 2•64 / 222 = 57,65%
w(C) = 1•12 / 222 = 5,4%
w(o) = 3+2•16 / 222 = 36%
w(H) = 2•1 / 222 = 0,9%
H2SO4:
M(H2SO4)=98
w(H)= 2•1 / 98 = 2,04%
w(S) = 1•32 / 98 = 32,65%
w(O) = 4•16 / 98 = 65.3%
ах..да..еще нужно нужно умножать на 100%..