дано
N(H2O) = 4.62*10²⁴ молекул = 46.2*10²³
N(C12H22O11) = 0.2*10²³ молекул
m(ppa)-?
используем формулу
N = n*N(A)
n = m/M
m(H2O) = N(H2O)*M(H2O) / N(A) = 46.2*10²³ * 18 / 6.02*10²³ = 138.14 g
m(C12H22O11) = N(C12h22O11) * M(C12H22O11) / N(A)
m(C12H22O11) = 0.2*10²³*342 / 6.02*10²³=11.36 g
m(ppa) = m(H2O)+m(C12H22O11)= 138.14+11.36 = 149.5 g
ответ 149.5 г
2)
дано
m(HCL) = 7.3 g
m(KOH)-?
KOH+HCL-->KCL+H2O
M(HCL)= 36.5 g/mol
n(HCL) = m/M = 7.3/36.5 = 0.2 mol
n(HCL) = n(KOH)= 0.2 mol
M(KOH) = 56 g/mol
m(KOH) = n*M = 0.2*56 = 11.2 g
ответ 11.2 г
Mg + Cl2 = MgCl2
MgCl2 + 2KOH = Mg(OH)2\/ + 2KCl
Mg(OH)2 + 2HNO3 = Mg(NO3)2 + 2H2O
2Mg(NO3)2 t™ = 2MgO + 4 NO2^ + O2^
4NO2 + 2H2O + O2 = 4HNO3
2) Pb -> PbO -> Pb(OH)2 -> (CH3COO)2Pb -> PbI2
2Pb + O2 = 2PbO
PbO + H2O = Pb(OH)2
Pb(OH)2 + 2CH3COOH = (CH3COO)2Pb + 2H2O
(CH3COO)2Pb + 2KI = PbI2\/ + 2 CH3COOK
3) Al -> Al2S3 -> H2S -> H2SO4 -> H2 -> HBr -> KBr
2 Al + 3S t° = Al2S3
Al2S3 + 6 HCl = 2 AlCl3 + 3H2S^
CuSO4 + H2S = H2SO4 + CuS\/
Fe + H2SO4 = FeSO4 + H2^
H2 + Br2 t° = 2HBr^
KOH + HBr = KBr + H2O
Отметь как лучший ответ.