1) P2O5 + 6KOH -->2K3PO4+3H2O
2) 3K20 + 2H3PO4 -->2K3PO4+3H2O
3) CO + NaOH--> HCOONa
4) Li2O + 2HCl -->2LiCL+H2O
5) 4P + 5O2 -->2P2O5
6) SO3 + 2KOH -->K2SO4+H2O
7) Be(OH2) + 2HCl -->BeCL2+2H2O
8) 2Al + 6HCl -->2AlCL3+3H2
дано
m(ppa H2SO4) = 200 g
W(H2SO4) = 5%
m(BaSO4)-?
m(H2SO4) = 200 *5% / 100% = 10 g
Ba(NO3)2+H2SO4-->BaSO4+2HNO3
M(Ba(NO3)2) = 261 g/mol
n(Ba(NO3)2) = m/M = 10 / 261 = 0.04 mol
n(Ba(NO3)2) = n(BaSO4) = 0.04 mol
M(BaSO4) = 233 g/mol
m(BaSO4) =n*M = 0.04 * 233 = 9.32 g
ответ 9.32 г
1) 2Al + 6HCl = 2AlCl3 + 3H2
2Al + 6H + 6Cl = 2Al + 6Cl + 6H
2) AlCl3 + 3NaOH = 3NaCl + Al(OH)3
Al + Cl3 + 3Na + 3OH = 3Na + 3Cl + Al(OH)3
Al + 3OH = Al(OH)3
3) 2Al(OH)3 = Al2O3 + 3H2O
2Al(OH)3 = 2Al + 3O + 3H2O
4) Al2O3 + 2NaOH + 3H2O = 2Na[Al(OH)4]
2Al + 3O + 2Na + 2OH + 3H2O = 2Na + 2Al(OH)4
2Al + 3O + 2OH + 3H2O = 2Al(OH)4
5) 2Na[Al(OH)4] + 3Na2SO4 = Al2(SO4)3 + 8NaOH
2Na + 2Al(OH)4 + 6Na + 3SO4 = 2Al + 3SO4 + 8Na + 8OH
2Al(OH)4 = 2Al + 8OH
6) Al2(SO4)3 + 6NaOH = 2Al(OH)3 + 3Na2SO4
2Al + 3SO4 + 6Na + 6OH = 2Al(OH)3 + 6Na + 3SO4
2Al + 6OH = 2Al(OH)3
7) Al(OH)3 +3HCl = 3H2O + AlCl3
Al(OH)3 + 3H + 3Cl = 3H2O + Al + 3Cl
Al(OH)3 + 3H = 3H2O + Al
8) AlCl3 + 4NaOH (избыток) = 3NaCl + Na[Al(OH)4]
Al + 3Cl + 4Na + 4OH = 3Na + 3Cl + Na + Al(OH)4
Al + 4OH = Al(OH)4