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1. Найдем количество вещества Са(ОН)2:
n=m/M=14,8/74=0,2 моль
2. Найдем массу хлорида кальция:
n((Ca(OH)2)=n(CaCl2)=0,2 моль
m(CaCl2)=n*M=0,2*110=22 г