CaCl2
W(Ca) = Ar(Ca) * n / Mr(CaCl2) *100% = 40 * 1 / 110 *100% = 36,36%
W(Cl) = Ar(Cl) * n / Mr(CaCl2) * 100% = 35 * 2 / 110 *100% =63,63%
Na3PO4
W(Na) = Ar(Na) * n / Mr(Na3PO4 *100% = 23 * 3 / 164 *100% = 42%
W(P) = Ar(P) * n / Mr(Na3PO4) *100% = 31 * 1 / 164 *100% = 18,9%
W(O) = Ar(O) * n / Mr(Na3PO4) * 100% = 16 * 4 / 164 *100% = 39%
Fe(OH)3
W(Fe) = Ar(Fe) * n / Mr(Fe(OH)3) *100% = 56 * 1 / 107 * 100% = 52,33%
W(O) = Ar(O) * n / Mr(Fe(OH)3 *100% = 16 * 3 / 107 *100% = 44,86%
W(H) = Ar(H) * n / Mr(Fe(OH)3) *100% = 1*3 / 107 *100% = 2,8%
n=m/M(Mr) M=Mr Mr(CCl4)= 154 M=154
n(CCL4)=38,5/154=0,25( моль)
n(СCl4)/n(CH4)=1/1, след.,n(CH4)=0,25 моль по условию реакции
V=n*Vm V(CH4)= 0,25*22,4=5,6(л)
ответ: 5,6л