CIVII20II7
Объяснение:
определим валентность хлора в его соединении с кислородом — Cl2O7.
1. Записываем известную валентность кислорода над формулой. Неизвестную валентность обозначаем буквой x:
Clx2OII7.
2. Находим сумму единиц валентности каждого элемента. Для этого его валентность умножаем на число атомов:
x⋅2=2⋅7.
3. Вычисляем x:
2x=14,x=14:2=7.
Валентность хлора равна VII:
ClVII2OII7.
Составление формулы бинарного соединения по валентностям химических элементов
Если известны валентности двух элементов, то можно составить формулу их соединения.
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К₂СО₃ +2НСl =2KCl+Н₂О +СО₂
По реакции видно, что из 1моля карбоната калия образуется 1 моль углекислого газа.
! моль СО₂ это 22,4л. Это же у нас и образовалось! Значит карбоната калия в золе был 1 моль.
Mr(К₂СО₃Ш=2·39+12+3·16=138г/моль.
А золы ведь взято 150г! Значит поташа там:
(138:150)·100%= 92%