2Na3PO4 + 3CaI2 = 6NaI + Ca3(PO4)2
6Na(+) + 2PO4(3-) + 3Ca(2+) + 6I(+) = 6Na(+) + 6I + Ca3(PO4)2
1) a) СuBr₂+2AgNO₃ = Cu(NO₃)₂ + 2AgBr↓
Cu⁺² + 2Br⁻ + 2Ag⁺ + 2NO₃⁻ = Cu⁺²+2NO₃⁻ + 2AgBr
2Ag⁺ + 2Br⁻ = 2AgBr
Cu(NO₃)₂ + H₂O ⇔ CuOHNO₃ +HNO₃
Cu⁺² + 2NO₃⁻ + OH⁻ + H⁺ = Cu⁺² + OH⁻ + 2NO₃⁻ + H⁺
СuOHNO₃ + NH₃ + H₂O = Cu(OH)₂↓ + NH₄NO₃
Cu²⁺ + OH⁻ + NO₃⁻ + NH₃ + OH⁻ + H⁺ = Cu(OH)₂ + NH₄⁺ + NO₃⁻
Cu²⁺ + OH⁻ + NH₃ + OH⁻ + H⁺ = Cu(OH)₂ + NH₄⁺
Cu(OH)₂ (t°)= CuO + H₂O
б) CO₂+ KOH = KHCO₃
CO₂ + K⁺ + OH⁻ = K⁺ + H⁺ + CO₃⁻²
CO₂+ OH⁻ = H⁺ + CO₃²⁻
KHCO₃ + KOH = K₂CO₃ + H₂O
K⁺ + H⁺ + CO₃⁻² + K⁺ + OH⁻ = 2K⁺ + CO₃⁻² + H⁺ + OH⁻
K₂CO₃ + Ca(OH)₂ = 2KOH + CaCO₃↓
2K⁺ + CO₃⁻² + Ca⁺² + 2OH⁻ = 2K⁺ + 2OH⁻ + CaCO₃
Ca⁺² + CO₃⁻² = CaCO₃
CaCO₃ + 2HCL = CaCL₂ + CO₂ + H₂O (H₂CO₃ сразу распадается)
CaCO₃ + 2H⁺ + 2CL⁻ = Ca⁺² + 2CL⁻ + CO₂ + H⁺ + OH⁻
CaCO₃ + H⁺ = Ca⁺² + CO₂ + OH⁻
2) SnBr₂ + H₂O ⇔ SnOHBr + HBr
PbOHBr + H₂O ⇔ Pb(OH)₂ + HBr
LiHS + H₂O ⇔ LiOH + H₂S
1) n(K) = 5,6г : 39г/моль ≈ 0,14моль
2) n(H2O) = n(K) = 0,14моль
3) V(H2O) = 0,14моль * 22,4л/моль = 3,136л ≈ 3,14л