СН4
W(C) = Ar(C) * n / Mr(CH4) *100% = 12 * 1 / 16 *100% = 75%
W(H) = Ar(H) * n / Mr(CH4) *100% = 1 * 4 / 16 *100% = 25 %
С2Н2
W(C) = Ar(C) * n / Mr(C2H2) *100% = 12*2 / 26 *100% = 92%
W(H) = Ar(H) * n / Mr(C2H2) *100% = 1 *2 / 26 * 100% = 8%
С2Н6
W(C) = Ar(C) * n / Mr(C2H6) *100% = 12 *2 / 30 *100% = 80%
W(H) = Ar(H) * n / Mr(C2H6) *100% = 1 *6 | 30 * 100% = 20%
C2H4
W(C) = Ar(C) * n | Mr(C2H4) * 100% = 12 *2 / 28 *100% = 85,7%
W(H) = Ar(H) *n / Mr(C2H4) * 100% = 1*4 / 28 *100% = 14,3%
С6Н6
W(C) = Ar(C) * n / Mr(C6H6) *100% = 12 *6 / 78 *100% = 92,3%
W(H) = Ar(H) * n / Mr(C6H6) *100% = 1 * 6 / 78 *100% = 7,7%
2S +3O2-->2SO3 M(S)=32g/mol , Vm=22.4L/mol
2*32 2*22.4
8000/64 = X/44.8
X=5600 л
ответ 5600 л