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Объяснение:
Глюкоза
Мг(С6Н12О6) = 6Аг(С)+12Аг(Н)+6Аг(О) = 6*12+12*1+6*16 = 180
ω(С) = 72/180*100% = 40%
ω(Н) = 12/180*100% = 6,67%
ω(О) = 100% - 40% - 6,67% = 53,33%
Фруктоза
Мг(С12Н22О11) = 12Аг(С) + 22Аг(Н) + 11Аг(О) = 12*12+22*1+11*16 = 342
ω(C) = 12*12/342*100% = 42.11%
ω(Н) = 22*1/342*100% = 6,43%
ω(О) = 100% - 42,11% - 6,43% = 51,46%