Решить . mg - mgo - mg3(po4)2 - mg(oh)2 - mgo - mg - id821658820210330 от donik223 30.03.2021 00:00

Question

Химия: Решить . mg - mgo - mg3(po4)2 - mg(oh)2 - mgo - mg

donik223 · Accepted Answer

Дано

m1(ppa H2SO4) = 126 g

W1(H2SO4) = 10%

m2(ppa H2SO4) = 344 g

W2(H2SO4) = 18%

m3(H2SO4) = 40 g

m(H2O) = 100 g

W общ (H2SO4)-?

m1(H2SO4) = 126* 10% / 100% = 12.6 g

m2(H2SO4) = 344*18% / 100% = 61.92 g

m общ (H2SO4) = m1(H2SO4)+m2(H2SO4 + m3(H2SO4)

m общ (H2SO4)= 12.6 + 61.92+40 = 114.52 g

m общ (ppa H2SO4) = m1(ppa H2SO4) + m2(рра H2SO4) + m3(H2O)+m3 (H2SO4

m общ (ppa H2SO4) = 126 + 344 + 100+40 = 610 g

W общ (H2SO4) = m общ (H2SO4) / m общ (ppa H2SO4) * 100%

W общ (H2SO4) = 114.52 / 610 * 100% = 18.77%

ответ 18.77 %

Решить . mg - mgo - mg3(po4)2 - mg(oh)2 - mgo - mg

MOGZ ответил