Question

523 - г-и (г д е ж з и) 524 г

Answer 1

#523

a)

$\frac{2}{9} x + \frac{4}{9} x = \frac{2x}{9} + \frac{4x}{9} = \frac{2x + 4x}{9} = \frac{6x}{9} = \frac{2x}{3} = \frac{2}{3} x$

б)

$\frac{5}{7} a - \frac{9}{14} a = \frac{5a}{7} - \frac{9a}{14} = \frac{10a}{14} - \frac{9a}{14} = \frac{10a - 9a}{14} = \frac{a}{14} = \frac{1}{14} a$

в)

$\frac{7}{12} m - \frac{5}{12} m = \frac{7 - 5}{12} m = \frac{2}{12} m = \frac{1}{6} m$

г) и д)

$\frac{5}{6} b - \frac{3}{4} b = \frac{10}{12} b - \frac{9}{12}b = \frac{1}{12} b$

$\frac{19}{6} z + \frac{2}{3} z = \frac{19}{6} + \frac{4}{6} z = \frac{23}{6} z$

е)

$\frac{11}{4} t - \frac{15}{8} t = \frac{22}{8} t - \frac{15}{8} t = \frac{7}{8} t$

#524

ж)5/18x+(5/12x-1/4x)=5/18x+(5/12x-3/12x)=10/36x+(15/36x-9/36x)=10/36x+6/36x=16/36x=4/9x

з)11/18n-(5/18n+1/6n)=11/18n-(5/18n+3/18n)=

11/18n-8/18n=3/18n=1/6n

и)2/3c+1/9c-7/9c=6/9c+1/9c-7/9c=0

к)k-1/7k=7/7k-1/7k=6/7k

л)3/11y+8/11y=11/11y=y

м)3/5b+b=3/5b+5/5b=8/5b