1) y=x2+3; x=1; x=2; y=0. 2) y=−x2+9x; x=1; x=4; y=0. 3) y=cos+1; x=0; x=П/3; y=0. - id1201126820220705 от karinohka2006 05.07.2022 11:48

Question

Математика: 1) y=x2+3; x=1; x=2; y=0. 2) y=−x2+9x; x=1; x=4; y=0. 3) y=cos+1; x=0; x=П/3; y=0.

karinohka2006 · Accepted Answer

-12 * (-8.6) -9.4 = 1032 - 9.4

   120 * 86 60*86    12*86
   = =
-12 * (- 8целых6/10) = -12 * (- 86/10) = 10    5    1

= 12*86 = 1032

   1032    94 10320 -94
      - =   =
1032 - 9.4 = 1032 - 9целых4/10 =    1    10 10

= 10226/10 = 5113/5

1) y=x2+3; x=1; x=2; y=0.2) y=−x2+9x; x=1; x=4; y=0.3) y=cos+1; x=0; x=П/3; y=0.

MOGZ ответил

1) y=x2+3; x=1; x=2; y=0.

2) y=−x2+9x; x=1; x=4; y=0.

3) y=cos+1; x=0; x=П/3; y=0.