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игорь800
игорь800
17.10.2021 22:06 •  Математика

3.8m(2.8m+0.7m) при m=2.4 и при m=8.57

👇
Ответ:
089280ig
089280ig
17.10.2021

во второй скобке видим общий множитель м, выносим его за скобку, т.е.получаем: 3,8м^2(2,8+0,7)=3,8*2,4^2*3,5=76,608 или с округлением это будет примерно 79,6
3,8*8,57^2*3,5=976,81717 или с округлением это будет примерно 976,8

4,8(70 оценок)
Ответ:
АВатар1765
АВатар1765
17.10.2021

1) при m=2,4

    3,8*2,4*(2,8*2,4+0,7*2,4) = 9,12*(6,72+1,68) = 9,12*8,4 = 76,608=76,61

2) при m = 8,57

    3,8*8,57*(2,8*8,57+0,7*8,57) = 32,566*(23,996+5,999)= 32,566*29,995 = 976,81717= =976,82

4,4(36 оценок)
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Ответ:
tseng7788
tseng7788
17.10.2021

Пошаговое объяснение:

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4,6(44 оценок)
Ответ:
Zxcvbnm900
Zxcvbnm900
17.10.2021

6,8 часа потратил катер на путь по реке от одного причала до другого и обратно.

Пошаговое объяснение:

Собственная скорость катера 17 км/ч, скорость течения реки 3 км/ч

Значит:

17 + 3 = 20 км/ч скорость катера по течению реки

17 - 3 = 14 км/ч скорость катера против течения реки

56/20 + 56/14 = 2,8 + 4 = 6,8 (часа) потратил катер на путь по реке от одного причала до другого и обратно.

Проверим:

Туда и обратно катер проплыл одно и то же расстояние - 56 км.

20 * 2,8 = 14 * 4

56 (км) = 56 (км)- катер проплыл по течению реки и против течения одно и то же расстояние - 56 км.

4,8(73 оценок)
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