Question

Раскройте скобки
(х+4)²=
(2х+1)²=
(х+у)²=
(х+2)²=

Answer 1

(х+4)²=  x²+8x+16

(2х+1)²=  4x²+4x+1

(х+у)²=  x²+2xy+y²

(х+2)²= x²+4x+4

Answer 2

${( x+ 4)}^{2} = {x}^{2} + 2x \times 4 \times {4}^{2} = {x}^{2} + {8}^{2} + {4}^{2} = {x}^{2} + 8x + 16$

${(2x + 1)}^{2} = {4x}^{2} + 4x + 1 = {4x}^{2} + 4x + 1$

${(x + y)}^{2} = {x}^{2} + 2xy + {y}^{2}$

${(x + 2)}^{2} = {x}^{2} + 2x \times 2 + {2}^{2} = {x}^{2} + 4x + 4$