Question

решить. Вместе с решением. 1) х^3 - 5х^2 + 6х = 0
2) (х^2 - 5)(х^2 - 4х +3) = 0

Answer 1

1)

$x^{3} -5x^{2} +6x = 0\\x(x^{2} -5x+6) = 0 \\x(x-2)(x-3) = 0$

[ x = 0

[ x - 2 = 0     =>     x = 2

[ x - 3 = 0     =>     x = 3

ответ :  0 , 2 , 3

2)

$(x^{2} -5)(x^{2} -4x+3) = 0$

$(x^{2} -5)(x-3)(x-1) = 0$

[ $x^{2}-5 = 0$

[ $x-3 = 0$

[ $x - 1 =0$

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[ $x = \sqrt{5}$

[ $x = -\sqrt{5}$

[ $x = 3$

[ $x = 1$

ответ :  -√5 , 1 , √5 , 3