1) 25 ⋅ 78 ⋅ 4; 4) 49 ⋅ 9 + 21 ⋅ 9; 2) 2 ⋅ 49 ⋅ 50; 5) 316 ⋅ 5 − 216 ⋅ 5.
3) 3 ⋅ 5 ⋅ 8 ⋅ 3 6) 239 ⋅ 47 + 239 ⋅ 53.

Question

Математика: 1) 25 ⋅ 78 ⋅ 4; 4) 49 ⋅ 9 + 21 ⋅ 9; 2) 2 ⋅ 49 ⋅ 50; 5) 316 ⋅ 5 − 216 ⋅ 5. 3) 3 ⋅ 5 ⋅ 8 ⋅ 3 6) 239 ⋅ 47 + 239 ⋅ 53.

Лубничка · Accepted Answer

ответ: 0,52Пошаговое объяснение:Пусть:А = кофе за­кон­чит­ся в пер­вом ав­то­ма­те,В = кофе за­кон­чит­ся во вто­ром ав­то­ма­те.Тогда:A·B = кофе за­кон­чит­ся в обоих ав­то­ма­тах,A + B = кофе за­кон­чит­ся хотя бы в одном ав­то­ма­те.По усло­вию получается P(A) = P(B) = 0,3; P(A·B) = 0,12.Со­бы­тия A и B сов­мест­ные, ве­ро­ят­ность суммы двух сов­мест­ных со­бы­тий равна сумме ве­ро­ят­но­стей этих со­бы­тий, умень­шен­ной на ве­ро­ят­ность их про­из­ве­де­ния:P(A + B) = P(A) + P(B) − P(A·B)...

1) 25 ⋅ 78 ⋅ 4; 4) 49 ⋅ 9 + 21 ⋅ 9; 2) 2 ⋅ 49 ⋅ 50; 5) 316 ⋅ 5 − 216 ⋅ 5. 3) 3 ⋅ 5 ⋅ 8 ⋅ 3 6) 239 ⋅ 47 + 239 ⋅ 53.

MOGZ ответил

1) 25 ⋅ 78 ⋅ 4; 4) 49 ⋅ 9 + 21 ⋅ 9; 2) 2 ⋅ 49 ⋅ 50; 5) 316 ⋅ 5 − 216 ⋅ 5.
3) 3 ⋅ 5 ⋅ 8 ⋅ 3 6) 239 ⋅ 47 + 239 ⋅ 53.