Question

упр 398
Под цифрой один, и два
заранее">

Answer 1

$1 - \frac{7}{10} = \frac{10}{10} - \frac{7}{10} = \frac{3}{10}$

$1 - \frac{1}{4} = \frac{4}{4} - \frac{1}{4} = \frac{3}{4}$

$1 - \frac{4}{7} = \frac{7}{7} - \frac{4}{7} = \frac{3}{7}$

$1 - \frac{2}{9} = \frac{9}{9} - \frac{2}{9} = \frac{7}{9}$

$1 - \frac{10}{13} = \frac{13}{13} - \frac{10}{13} = \frac{3}{13}$

$1 - \frac{9}{10} = \frac{10}{10} - \frac{9}{10} = \frac{1}{10}$

$1 - \frac{8}{11} = \frac{11}{11} - \frac{8}{11} = \frac{3}{11}$

$1 - \frac{3}{20} = \frac{20}{20} - \frac{3}{20} = \frac{17}{20}$

$1 - \frac{5}{12} = \frac{12}{12} - \frac{5}{12} = \frac{7}{12}$

$1 - \frac{5}{8} = \frac{8}{8} - \frac{5}{8} = \frac{3}{8}$

$1 - \frac{1}{17} = \frac{17}{17} - \frac{1}{17} = \frac{16}{17}$

$1 - \frac{14}{15} = \frac{15}{15} - \frac{14}{15} = \frac{1}{15}$